4d^2-d-3=-d^2

Solution for 4d^2-d-3=-d^2 equation:

4d^2-d-3=-d^2

We move all terms to the left:

4d^2-d-3-(-d^2)=0

We add all the numbers together, and all the variables

4d^2-(-d^2)-1d-3=0

We get rid of parentheses

4d^2+d^2-1d-3=0

We add all the numbers together, and all the variables

5d^2-1d-3=0

a = 5; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·5·(-3)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{61}}{2*5}=\frac{1-\sqrt{61}}{10}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{61}}{2*5}=\frac{1+\sqrt{61}}{10}
$